Let's analyze the stability of the given carbocations:
A. Triphenyl carbocation:
The positive charge is stabilized by resonance with three phenyl rings.
B. Diphenyl carbocation:
The positive charge is stabilized by resonance with two phenyl rings.
C. Tropylium carbocation:
This is a cyclic carbocation with 6 π electrons. It is aromatic and highly stable due to resonance and delocalization of charge.
D. Secondary carbocation:
This is a relatively simple carbocation stabilized mainly by the inductive effect of alkyl groups.
The stability of carbocations increases with the number of alkyl groups attached to the positively charged carbon. Additionally, resonance stabilization significantly enhances the stability of the carbocation.
Final Order of Stability:
$ C > A > B > D $
Final Answer:
The final answer is $ C > A > B > D $.
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
A hydrocarbon which does not belong to the same homologous series of carbon compounds is
Let $ f(x) = \begin{cases} (1+ax)^{1/x} & , x<0 \\1+b & , x = 0 \\\frac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2} & , x>0 \end{cases} $ be continuous at x = 0. Then $ e^a bc $ is equal to
Total number of nucleophiles from the following is: \(\text{NH}_3, PhSH, (H_3C_2S)_2, H_2C = CH_2, OH−, H_3O+, (CH_3)_2CO, NCH_3\)