The coordinates of a particle with respect to origin in a given reference frame is \( (1, 1, 1) \) meters. If a force of \( \mathbf{F} = \hat{i} - \hat{j} + \hat{k} \) acts on the particle, then the magnitude of torque (with respect to origin) in the z-direction is:
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The magnitude of the torque in a given direction can be calculated by finding the cross product of the position and force vectors and extracting the appropriate component.
The torque is given by the cross product of the position vector \( \mathbf{r} \) and the force vector \( \mathbf{F} \).
\[
\mathbf{\tau} = \mathbf{r} \times \mathbf{F}
\]
- Position vector \( \mathbf{r} = (1, 1, 1) \)
- Force vector \( \mathbf{F} = (1, -1, 1) \)
The torque in the z-direction is:
\[
\tau_z = r_x F_y - r_y F_x = 1 \times (-1) - 1 \times 1 = -2
\]
The magnitude of the torque in the z-direction is \( 1 \).
Thus, the correct answer is 1.