Step 1: Recall the formula.
\[
\text{Concentration (g/L)} = Molarity \times Molar \, Mass
\]
Step 2: Write known values.
- Molarity = 0.2 M
- Molar mass of H$_2$SO$_4$ = (2 × 1) + (32) + (16 × 4)
= 2 + 32 + 64
= 98 g/mol
Step 3: Calculate concentration.
\[
\text{Concentration} = 0.2 \times 98 = 19.6 \, g/500 \, ml
\]
But since we want concentration per litre (1000 ml):
\[
\text{Concentration} = 0.2 \times 98 = 19.6 \times 2 = 39.2 \, g/L
\]
Step 4: Final Answer.
Thus, the concentration of 0.2 M H$_2$SO$_4$ solution is:
\[
\boxed{39.2 \, g/L}
\]