Question:

The complex number $z$ satisfying the condition arg $\frac {z-1} {z+1} = \frac {\pi} {4}$

Updated On: Jul 7, 2022
  • a straight line
  • a circle
  • a parabola
  • none of these
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The Correct Option is B

Solution and Explanation

Let $z = x + iy$, then $\frac{z-1}{z+1}=\frac{x+iy-1}{x+iy+1}$ $=\frac{\left(x-1\right)+iy}{\left(x+1\right)+iy} \cdot \frac{\left(x+1\right)-iy}{\left(x+1\right)-iy}$ $=\frac{\left(x^{2}+y^{2}-1\right)+i\left(2y\right)}{\left(x+1\right)^{2}+y^{2}}$ Since $arg. \frac{z-1}{z+1}=\frac{\pi}{4}$ $\therefore tan \,\frac{\pi}{4}=\frac{2\,y}{x^{2}+y^{2}-1}$ $\Rightarrow 1=\frac{2y}{x^{2}+y^{2}-1}$ $\Rightarrow x^{2}+y^{2}-1=2y$ $\Rightarrow x^{2}+y^{2}-2y-1=0$ which represents a circle.
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Concepts Used:

Complex Number

A Complex Number is written in the form

a + ib

where,

  • “a” is a real number
  • “b” is an imaginary number

The Complex Number consists of a symbol “i” which satisfies the condition i^2 = −1. Complex Numbers are mentioned as the extension of one-dimensional number lines. In a complex plane, a Complex Number indicated as a + bi is usually represented in the form of the point (a, b). We have to pay attention that a Complex Number with absolutely no real part, such as – i, -5i, etc, is called purely imaginary. Also, a Complex Number with perfectly no imaginary part is known as a real number.