The co-ordination number and the oxidation state of the element $'M'$ in the complex $[ M(en)_{2}(C_{2}O_{4})]NO_{2}$ $\{$ where (en) is ethane-1,2-diamine) are, respectively
- $6$ and $3$
- $6$ and $2$
- $4$ and $2$
- $4$ and $3$
The Correct Option is A
Solution and Explanation
The correct option s(A): 6 and 3.
For the given coordinate compound.
\([M (en)_2 (C_2O_4)]NO_2\)
(i) \(\because\) All the (3) ligands are bi dented thus its coordinate number \(=6\)
(ii) Oxidation number of \(M\) will be
\(x+0+2 \times(-2)=0-1\)
\(\therefore \,x\) (oxidation number of \(M)= 3\)
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.