Question:
The circuit has two oppositely connected ideal diodes in parallel. What is the current flowing in the circuit ?
The circuit has two oppositely connected ideal diodes in parallel. What is the current flowing in the circuit ?
Updated On: Jul 29, 2022
- $1.71\, A$
- $2.00\, A$
- $2.31\, A$
- $1.33\, A$
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The Correct Option is B
Solution and Explanation
In the given circuit diode D, is reverse biased while $D_2$ is forward biased, so the circuit can be redrawn as:
[$\because$ For ideal diodes, reverse biased means open and forward biased means short]
Apply $KVL$ to get current flowing through the circuit
$-12+4i+2i=0 \Rightarrow i=\frac{12}{6}=2A$
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Concepts Used:
P-n Junction
A P-N junction is an interface or a boundary between two semiconductor material types, namely the p-type and the n-type, inside a semiconductor.
Biasing conditions for the p-n Junction Diode:
in p-n junction diode two operating regions are there:
- P-type
- N-type
There are three biasing conditions for p-n junction diode are as follows:
- Zero bias: When there is no external voltage applied to the p-n junction diode.
- Forward bias: P-type is connected to positive terminal of the voltage potential while n-type is connected to the negative terminal.
- Reverse bias: P-type is connected to negative terminal of the voltage potential while n-type is connected to the positive terminal.