Question

The charge present in a doubly ionized helium atom is

• A. 1.6×10^-19C
• B. 6.4×10^-19C
• C. 4.8×10^-19C
• D. 8.0×10^-19C
• E. 3.2×10^-19C

Answer 1

Answer: (E)

In a doubly ionized helium atom (He\(^{2+}\)), two electrons are removed, leaving only the nucleus with a charge. A helium atom has 2 protons, and since the charge of a proton is \( +1.6 \times 10^{-19} \, \text{C} \), the charge of the doubly ionized helium atom is: \[ \text{Charge} = 2 \times 1.6 \times 10^{-19} \, \text{C} = 3.2 \times 10^{-19} \, \text{C} \]

The correct option is (E) : 3.2×10^-19C

Answer 2

A doubly ionized helium atom (He²⁺) has lost both of its electrons.  

Each electron carries a charge of: $$ e = 1.6 \times 10^{-19} \, \text{C} $$ 
So the total positive charge (from 2 protons) is: $$ q = 2e = 2 \times 1.6 \times 10^{-19} = 3.2 \times 10^{-19} \, \text{C} $$ 

Answer: \( \boxed{3.2 \times 10^{-19} \, \text{C}} \)