Question:
The Cartesian equation of the line passing through (7, 5, 3) and perpendicular to the plane 3x + 2y + z = 6 is
The Cartesian equation of the line passing through (7, 5, 3) and perpendicular to the plane 3x + 2y + z = 6 is
Updated On: Jun 10, 2024
- \(\frac{x-7}{3}=\frac{y-5}{2}=\frac{z-3}{1}\)
- \(\frac{x-3}{7}=\frac{y-2}{5}=\frac{z-1}{3}\)
- \(\frac{x-3}{7}=\frac{y-2}{5}=\frac{z}{3}\)
- \(\frac{x-7}{3}=\frac{y-5}{1}=\frac{z-3}{2}\)
- \(\frac{x-4}{4}=\frac{y-3}{3}=\frac{z-2}{2}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{x-7}{3}=\frac{y-5}{2}=\frac{z-3}{1}\)
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