Step 1: Recall the concept.
Boiling point elevation is a colligative property, which depends on the number of solute particles in solution (van’t Hoff factor $i$).
Step 2: Compare solutes.
- Glucose and sucrose are non-electrolytes: $i = 1$.
- NaCl dissociates into 2 ions: $i = 2$.
- CaCl$_2$ dissociates into 3 ions: $i = 3$.
Step 3: Apply formula.
$\Delta T_b = i K_b m$. The greater the $i$, the higher the elevation in boiling point.
Step 4: Conclude.
CaCl$_2$ produces maximum number of particles, hence maximum boiling point elevation.
Final Answer:
\[
\boxed{1% \; CaCl_2}
\]
% Quciktip