Assuming the height of tower be h metres.
tan 30 = \(\frac{1}{\sqrt 3} = \frac{(h-10)}{base}\)
base = \((h-10)\times\sqrt3\)
tan 60 = \(\frac{h}{base}\)
base = \(\frac{h}{\sqrt3}\)
So, \((h-10) \times \sqrt3 = \frac{h}{\sqrt3}\)
\(3h - 30 = h\)
h = 15 metres,
Therefore, height of tower is 15 metres.
The shadow of a tower on level ground is $30\ \text{m}$ longer when the sun's altitude is $30^\circ$ than when it is $60^\circ$. Find the height of the tower. (Use $\sqrt{3}=1.732$.)