Assuming the height of tower be h metres.
tan 30 = \(\frac{1}{\sqrt 3} = \frac{(h-10)}{base}\)
base = \((h-10)\times\sqrt3\)
tan 60 = \(\frac{h}{base}\)
base = \(\frac{h}{\sqrt3}\)
So, \((h-10) \times \sqrt3 = \frac{h}{\sqrt3}\)
\(3h - 30 = h\)
h = 15 metres,
Therefore, height of tower is 15 metres.