Solution:
Carrier signal: $15 \sin(1000 \pi t)$
Modulating signal: $10 \sin(4 \pi t)$
The general form of a sinusoidal wave is $A \sin(2 \pi f t)$, where $A$ is the amplitude, $f$ is the frequency, and $t$ is time.
1. Carrier signal frequency $(f_c)$:
$$ 2 \pi f_c = 1000 \pi $$ $$ f_c = \frac{1000 \pi}{2 \pi} = 500 \text{ Hz} $$
2. Modulating signal frequency $(f_m)$:
$$ 2 \pi f_m = 4 \pi $$ $$ f_m = \frac{4 \pi}{2 \pi} = 2 \text{ Hz} $$
In amplitude modulation, the modulated signal contains the carrier frequency and two sideband frequencies:
Carrier frequency $(f_c) = 500 \text{ Hz}$
Lower sideband frequency $(f_c - f_m) = 500 \text{ Hz} - 2 \text{ Hz} = 498 \text{ Hz}$
Upper sideband frequency $(f_c + f_m) = 500 \text{ Hz} + 2 \text{ Hz} = 502 \text{ Hz}$
The frequencies present in the amplitude modulated signal are:
500 Hz (1)
498 Hz (4)
502 Hz (5)
Therefore, the correct answer is (4) (1), (4) and (5) only.

Let \( a \in \mathbb{R} \) and \( A \) be a matrix of order \( 3 \times 3 \) such that \( \det(A) = -4 \) and \[ A + I = \begin{bmatrix} 1 & a & 1 \\ 2 & 1 & 0 \\ a & 1 & 2 \end{bmatrix} \] where \( I \) is the identity matrix of order \( 3 \times 3 \).
If \( \det\left( (a + 1) \cdot \text{adj}\left( (a - 1) A \right) \right) \) is \( 2^m 3^n \), \( m, n \in \{ 0, 1, 2, \dots, 20 \} \), then \( m + n \) is equal to: