Question:

The adjoint of the matrix \[ A = \begin{pmatrix} 2 & 3
-3 & 5 \end{pmatrix} \] is

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To find the adjoint of a 2x2 matrix, compute the cofactor matrix and take its transpose.
Updated On: Jan 30, 2026
  • \( \begin{pmatrix} 5 & 3
    -3 & 2 \end{pmatrix} \)
  • \( \begin{pmatrix} 5 & -3
    3 & 2 \end{pmatrix} \)
  • \( \frac{1}{19} \begin{pmatrix} 5 & -3
    -3 & 2 \end{pmatrix} \)
  • \( \frac{1}{19} \begin{pmatrix} 5 & 3
    -3 & 2 \end{pmatrix} \)
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The Correct Option is A

Solution and Explanation

Step 1: Formula for the adjoint of a matrix.
The adjoint of a matrix is the transpose of its cofactor matrix. The cofactor matrix of \( A \) is obtained by computing the minor matrix for each element and applying the appropriate sign. For the given matrix \( A \), the adjoint matrix is: \[ \text{Adj}(A) = \begin{pmatrix} 5 & 3
-3 & 2 \end{pmatrix} \]
Step 2: Conclusion.
Thus, the adjoint of the matrix is \( \begin{pmatrix} 5 & 3
-3 & 2 \end{pmatrix} \), corresponding to option (A).
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