The correct option is( B): 35 days.
\(A=A_{0}e^{-λt}\)
⇒ 2 × 10–5 = 2.56 × 10–3e–λt
\(⇒e^{-λt}=\frac{1}{128}=[\frac{1}{2}]^7\)
\(⇒t=7t_{\frac{1}{2}}=35\,days\)
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to:
The rate at which an object covers a certain distance is commonly known as speed.
The rate at which an object changes position in a certain direction is called velocity.
Read More: Difference Between Speed and Velocity