Question:

The activity of a radioactive material is 2.56 × 10–3 Ci. If the half life of the material is 5 days, after how many days the activity will become 2 × 10–5 Ci?

Updated On: Jul 8, 2024
  • 30 days
  • 35 days
  • 40 days
  • 25 days
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The Correct Option is B

Solution and Explanation

The correct option is( B): 35 days.

\(A=A_{0}e^{-λt}\)

2 × 10–5 = 2.56 × 10–3e–λt

\(⇒e^{-λt}=\frac{1}{128}=[\frac{1}{2}]^7\)

\(⇒t=7t_{\frac{1}{2}}=35\,days\)

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