Question:
The 17th term of an AP exceeds its 10th term by 7. Find the common difference.
The 17th term of an AP exceeds its 10th term by 7. Find the common difference.
Updated On: Nov 3, 2023
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Solution and Explanation
We know that, For an A.P.,
\(a_n = a + (n − 1) d\)
\(a_{17} = a + (17 − 1) d\)
\(a_{17} = a + 16d\) ……. (i)
Similarly,
\(a_{10} = a + (10− 1) d\)
\(a_{10}= a + 9d\) ……. (ii)
It is given that,
\(a_{17} − a_{10} = 7\)
\((a + 16d) − (a + 9d) = 7\)
\(7d = 7\)
\(d = 1\)
Therefore, the common difference is 1.
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