The correct matching is as follows:
- A. Ethanol has a \( pK \) value of 15.9, so \( A - II \).
- B. Phenol has a \( pK \) value of 10.0, so \( B - I \).
- C. \( m \)-Nitrophenol has a \( pK \) value of 8.3, so \( C - IV \).
- D. \( p \)-Nitrophenol has a \( pK \) value of 7.1, so \( D - III \).
Hence, the correct matching is \( A - II, B - I, C - IV, D - III \).
The Correct Answer is: A-II, B-I, C-IV, D-III
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32