Question:

$\textbf{Match List I with List II}$
$\begin{array}{|c|c|c|} \hline \text{List I (Compound)} & \text{List II (p}K_a\text{ value)} \\ \hline \text{A. Ethanol} & \text{I. } 10.0 \\ \text{B. Phenol} & \text{II. } 15.9 \\ \text{C. m-Nitrophenol} & \text{III. } 7.1 \\ \text{D. p-Nitrophenol} & \text{IV. } 8.3 \\ \hline \end{array}$
$\text{Choose the correct answer from the options given below :-}$

Updated On: Nov 15, 2024
  • A-I, B-II, C-III, D-IV
  • A-IV, B-I, C-II, D-III
  • A-III, B-IV, C-I, D-II
  • A-II, B-I, C-IV, D-III
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The Correct Option is D

Solution and Explanation

The correct matching is as follows:  

- A. Ethanol has a \( pK \) value of 15.9, so \( A - II \).  
- B. Phenol has a \( pK \) value of 10.0, so \( B - I \).  
- C. \( m \)-Nitrophenol has a \( pK \) value of 8.3, so \( C - IV \).  
- D. \( p \)-Nitrophenol has a \( pK \) value of 7.1, so \( D - III \).  

Hence, the correct matching is \( A - II, B - I, C - IV, D - III \).

The Correct Answer is: A-II, B-I, C-IV, D-III

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