Question

Alkaline oxidative fusion of \(MnO_2\) gives “A” which on electrolytic oxidation in alkaline solution produces B. A and B respectively are:

• A. Mn$_2$O$_7$ and MnO$_4^-$
• B. MnO$_4^{2-}$ and MnO$_4^-$
• C. Mn$_2$O$_3$ and MnO$_4^{2-}$
• D. MnO$_4^{2-}$ and Mn$_2$O$_7$

Answer 1

The Correct Option is B

The process described involves the oxidative reactions of manganese compounds in alkaline solutions.

Alkaline Oxidative Fusion of \(MnO_2\): When \(MnO_2\) is subjected to oxidative fusion in an alkaline medium, it can form \(MnO_4^{2-}\) (manganate ion) under alkaline conditions. The reaction can be represented as:

\(2MnO_2 + 2OH^- + O_2 \rightarrow 2MnO_4^{2-} + H_2O\).

Electrolytic Oxidation of Product A: The product A formed from the oxidative fusion of \(MnO_2\) can be oxidized electrolytically in alkaline solution to form \(MnO_4^-\) (permanganate ion). The overall reaction is:

\(MnO_2 + 2e^- \rightarrow MnO_4^-\).

Thus, the products A and B formed in the given reaction sequence are: A = \(MnO_4^{2-}\) and B = \(MnO_4^-\).