Question

Taking the radius of the earth to be $6400 \,km$, by what percentage will the acceleration due to gravity at a height of $100\, km$ from the surface of the earth differ from that on the surface of the earth?

• A. About 1.5%
• B. About 5%
• C. About 8%
• D. About 3%

Answer 1

The Correct Option is D

Here, $R_{e}=600 \,km \,\,\,h=100 \,km$ Acceleration due to gravity at height, $h$ $g'=\frac{g R_{e}^{2}}{\left(R_{e}+h\right)^{2}}$ $g'=\frac{g(6400)^{2}}{(6400+100)^{2}}$ $=g\left(\frac{6400}{6500}\right)^{2}$ Percentage change in acceleration due to gravity $=\frac{g-g'}{g} \times 100$ $=\left(1-\frac{g'}{g}\right) \times 100 \%$ $=\left[1-\frac{6400}{6500}\right]^{2} \times 100 \%$ $=3.05 \%$