Possible selections are:
(1) 2 oranges, 1 red apple, 2 white apples.
(2) 2 oranges, 2 red apples, 1 white apple.
(3) 3 oranges, 1 red apple, 1 white apple.
The total number of ways for each case:
\( (1) \quad \binom{8}{2} \cdot \binom{7}{1} \cdot \binom{5}{2} = 1960. \)
\( (2) \quad \binom{8}{2} \cdot \binom{7}{2} \cdot \binom{5}{1} = 2940. \)
\( (3) \quad \binom{8}{3} \cdot \binom{7}{1} \cdot \binom{5}{1} = 1960. \)
Adding them:
1960 + 2940 + 1960 = 6860.
Final Answer:
\( \boxed{6860} \)
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