Possible selections are:
(1) 2 oranges, 1 red apple, 2 white apples.
(2) 2 oranges, 2 red apples, 1 white apple.
(3) 3 oranges, 1 red apple, 1 white apple.
The total number of ways for each case:
\( (1) \quad \binom{8}{2} \cdot \binom{7}{1} \cdot \binom{5}{2} = 1960. \)
\( (2) \quad \binom{8}{2} \cdot \binom{7}{2} \cdot \binom{5}{1} = 2940. \)
\( (3) \quad \binom{8}{3} \cdot \binom{7}{1} \cdot \binom{5}{1} = 1960. \)
Adding them:
1960 + 2940 + 1960 = 6860.
Final Answer:
\( \boxed{6860} \)
If the roots of the quadratic equation \( ax^2 + bx + c = 0 \) are real and equal, then:
A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers.
Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.
The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)
Read More: Nature of Roots of Quadratic Equation