- Statement-I: The melting point of neopentane is indeed higher than that of n-pentane because the structure of neopentane is more compact, and hence, the intermolecular forces are stronger, leading to a higher melting point. Therefore, Statement-I is correct.
- Statement-II: Neopentane can give more than one mono-substituted product because it has multiple possible positions for substitution. Thus, Statement-II is incorrect. Hence, the correct option is (4), as Statement-I is correct, but Statement-II is incorrect.
Which of the following compounds can exhibit geometrical isomerism, and why?
1) 2-butene
2) 1-butene ?
3) Pent-2-ene
4) But-2-yne
The compounds \( [\text{PtCl}_2(\text{NH}_3)_4]\text{Br}_2 \) and \( [\text{PtBr}_2(\text{NH}_3)_4]\text{Cl}_2 \) constitute a pair of:
Let \( C_{t-1} = 28, C_t = 56 \) and \( C_{t+1} = 70 \). Let \( A(4 \cos t, 4 \sin t), B(2 \sin t, -2 \cos t) \text{ and } C(3r - n_1, r^2 - n - 1) \) be the vertices of a triangle ABC, where \( t \) is a parameter. If \( (3x - 1)^2 + (3y)^2 = \alpha \) is the locus of the centroid of triangle ABC, then \( \alpha \) equals:
A line charge of length \( \frac{a}{2} \) is kept at the center of an edge BC of a cube ABCDEFGH having edge length \( a \). If the density of the line is \( \lambda C \) per unit length, then the total electric flux through all the faces of the cube will be : (Take \( \varepsilon_0 \) as the free space permittivity)