Question

How many isomers are possible for C$_4$H$_8$Cl$_2$ (including chain and positional)?

• A. 6
• B. 8
• C. 7
• D. 9

Hint:

Consider both chain and positional isomerism when calculating the number of possible isomers.

Answer 1

The Correct Option is B

Number of Isomers for \( \text{C}_4\text{H}_8\text{Cl}_2 \) 

Types of Isomers Considered:

• Chain isomers (n-butane vs isobutane)
• Positional isomers (placement of Cl atoms)

1. From Straight-Chain (n-butane):

Possible placements of two Cl atoms:

• 1,1-dichlorobutane
• 1,2-dichlorobutane (vicinal)
• 1,3-dichlorobutane
• 2,2-dichlorobutane
• 2,3-dichlorobutane

Total = 5 isomers

 

2. From Branched-Chain (isobutane):

Possible placements:

• 1,1-dichloro-2-methylpropane
• 1,2-dichloro-2-methylpropane
• 2,2-dichloro-2-methylpropane

Total = 3 isomers

 

✅ Final Answer:

\[ \boxed{8\ \text{isomers}} \]