To solve this problem, we need to evaluate the truthfulness of both given statements regarding chemical properties and reactions.
Statement I: Iron (III) catalyst, acidified \(K_2Cr_2O_7\) and neutral \(KMnO_4\) have the ability to oxidize \(I^–\) to \(I_2\) independently.
Explanation: Iron (III) does not act as an oxidizing agent to oxidize iodide \(I^–\) to iodine \(I_2\). Although acidified potassium dichromate \(K_2Cr_2O_7\) can oxidize \(I^–\) to \(I_2\), neutral potassium permanganate \(KMnO_4\) cannot effectively oxidize iodide ions in the neutral medium. Therefore, Statement I is false.
Statement II: Manganate ion is paramagnetic in nature and involves \(pπ – pπ\) bonding.
Explanation: The manganate ion \(MnO_4^{2-}\) is actually diamagnetic because all of its electrons are paired in the tetrahedral structure. Furthermore, \(dπ-pπ\) bonding, not \(pπ-pπ\), is typically involved. Therefore, Statement II is false.
Given the analyses, the correct option is: Both Statement I and Statement II are false. This conclusion is drawn based on the incorrect nature of both statements, as explained above.
Manganate ion \(MnO_4^{2-}\)has tetrahedral structure has only \(dπ – pπ\) \(π-bonds\).
\(Fe^{3+}\) is not used as a catalyst in the conversion of \(I^–\) to \(I_2\) by \(K_2Cr_2O_7\).
\(K_2Cr_2O_7\) oxidise \(I^–\) in acidic medium easily.
The correct answer is (B): Both Statement I and Statement II are false

All reactants need to overcome certain energy, better known as activation energy in order to form products. This activation energy is the difference between the energy of the transition state and the reactant species.
Catalysis of chemical reactions is generally divided into two categories: