Given below are two statements:
Statement I : Acceleration due to earth's gravity decreases as you go 'up' or 'down' from earth's surface
Statement II : Acceleration due to earth's gravity is same at a height '\(h\)' and depth ' \(d\) ' from earth's surface, if \(h = d\).
In the light of above statements, Choose the most appropriate answer form the options given below
• Statement I: The acceleration due to gravity (g') decreases when moving away from the earth's surface either upwards or downwards. The formulae for variations are:
\[g' = g\left(1 - \frac{2h}{R}\right)\] (for height h above surface)
\[g' = g\left(1 - \frac{d}{R}\right)\] (for depth d below surface)
Both variations indicate a decrease in g.
• Statement II: At equal height h and depth d (h = d), the values of g' are not the same. This is because g decreases faster as we go up (due to the inverse square law) compared to going down (due to linear variation inside the earth).
Thus, Statement I is correct, and Statement II is incorrect.
The acceleration due to gravity at a height of 6400 km from the surface of the earth is \(2.5 \, \text{ms}^{-2}\). The acceleration due to gravity at a height of 12800 km from the surface of the earth is (Radius of the earth = 6400 km)
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration.