The correct answer is 6
[MnBr6]–4
x – 6 = –4
x = + 2 Mn = 3d54s2
Mn+2 = 3d54s0
n = 5
\(μ = \sqrt{n(n+2)}\)
\(= \sqrt{35} ≈ 6 B.M.\)
Match the following:
Ions | Properties |
I. Zn2+ | i. d8 configuration |
II. Cu2+ | ii. Colourless |
III. Ni2+ | iii. µ = 1.73 BM |
Codes:
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.