Spin only magnetic moment of [MnBr6]4– is _____B.M. [round off to the closest integer]
Correct Answer: 6
Solution and Explanation
The correct answer is 6
[MnBr6]–4
x – 6 = –4
x = + 2 Mn = 3d54s2
Mn+2 = 3d54s0
n = 5
\(μ = \sqrt{n(n+2)}\)
\(= \sqrt{35} ≈ 6 B.M.\)
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.