Question:
Find an anti derivative (or integral) of the following functions by the method of inspection: sin2x - 4e3x
Find an anti derivative (or integral) of the following functions by the method of inspection: sin2x - 4e3x
Updated On: Oct 4, 2023
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Solution and Explanation
The anti derivative of (sin2x - 4e3x) is the function of x whose derivative is (sin2x - 4e3x) .
It is known that,
\(\frac{d}{dX}\bigg(-\frac{1}{2}cos2x-\frac{4}{3}e^{3x}\bigg) = \sin2x-4e^{3x}\)
Therefore, the anti derivative of (sin2x - 4e3x) is\(\bigg(-\frac{1}{2}cos2x-\frac{4}{3}e^{3x}\bigg) \) .
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Integral
The representation of the area of a region under a curve is called to be as integral. The actual value of an integral can be acquired (approximately) by drawing rectangles.
- The definite integral of a function can be shown as the area of the region bounded by its graph of the given function between two points in the line.
- The area of a region is found by splitting it into thin vertical rectangles and applying the lower and the upper limits, the area of the region is summarized.
- An integral of a function over an interval on which the integral is described.
Also, F(x) is known to be a Newton-Leibnitz integral or antiderivative or primitive of a function f(x) on an interval I.
F'(x) = f(x)
For every value of x = I.
Types of Integrals:
Integral calculus helps to resolve two major types of problems:
- The problem of getting a function if its derivative is given.
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