\(\alpha = \sin 36^\circ\) is a root of which of the following equation?
\(16x^4 - 10x^2 - 5 = 0\)
\(16x^4 + 20x^2 - 5 = 0\)
\(16x^4 - 20x^2 + 5 = 0\)
\(16x^4 - 10x^2 + 5 = 0\)
The Correct Option is C
Solution and Explanation
\(\alpha = \sin 36^\circ = x(say)\)
\(x = \frac{\sqrt{10} - 2\sqrt{5}}{4}\)
\(⇒\) \(16x^2 = 10 - 2\sqrt{5}\)
\(⇒\) \((8x^2 - 5)^2 = 5\)
\(⇒\) \(16x^4 - 80x^2 + 20 = 0\)
\(∴\) \(4x^4 - 20x^2 + 5 = 0\)
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Concepts Used:
Functions
A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.
Kinds of Functions
The different types of functions are -
One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.
Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.
Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.
Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.
Read More: Relations and Functions