Question:
Sides of a triangle are AB = 9, BC = 7, AC = 8. Then cos 3C equals to
Sides of a triangle are AB = 9, BC = 7, AC = 8. Then cos 3C equals to
Updated On: Apr 8, 2024
- \(\frac{-262}{343}\)
- \(\frac{181}{247}\)
- \(\frac{81}{93}\)
- \(\frac{-283}{285}\)
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The Correct Option is A
Solution and Explanation
The Correct answer is option is (A) : \(\frac{-262}{343}\)
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