Question:
satellite revolve in radius R has a time period of revolution T. Find time period of a satellite if orbital radius is 9R?
satellite revolve in radius R has a time period of revolution T. Find time period of a satellite if orbital radius is 9R?
Updated On: Jul 28, 2022
- $3\sqrt{3}T$
- 9T
- 27 T
- $9\sqrt{3}T$
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The Correct Option is C
Solution and Explanation
According to Kepler's law of periods
$T^{2}\,\propto\,R^{3}$
So,$\,\Rightarrow\, \frac{T_{1}}{T_{2}}=\left(\frac{R_{1}}{R_{2}}\right)^{\frac{3}{2}}$
$\Rightarrow\, \frac{T}{T_{2}}=\left(\frac{R}{9R}\right)^{\frac{3}{2}}\,=\frac{1}{27}\,\left[\because \,T_{1}=T\right]$
$T_{2}=27T$
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Concepts Used:
Keplers Laws
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T2 ∝ a3