Question:

Represent the following situations in the form of quadratic equations.

(i) The area of a rectangular plot is 528 \(m^2\). The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot. 

(ii) The product of two consecutive positive integers is 306. We need to find the integers.

(iii) Rohan’s mother is 26 years older than him. The product of their ages (in years) 3 years from now will be 360. We would like to find Rohan’s present age.

(iv) A train travels a distance of 480 km at a uniform speed. If the speed had been 8 km/h less, then it would have taken 3 hours more to cover the same distance. We need to find the speed of the train.

Updated On: Nov 1, 2023
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Solution and Explanation

(i) Let the breadth of the plot be x m.
Hence, the length of the plot is (2x + 1) m.

 Area of a rectangle = Length × Breadth 
∴ 528 = x (2x + 1) 
⇒ \(2x^2 + x -528\) = 0


(ii) Let the consecutive integers be x and x + 1.

It is given that their product is 306. 
∴ x(x+1) = 306
⇒ \(x^2 +x -306 =0\)


(iii) Let Rohan’s age be x.
Hence, his mother’s age = x + 26

3 years hence, 
Rohan’s age = x + 3
Mother’s age = x + 26 + 3 = x + 29

It is given that the product of their ages after 3 years is 360.
∴ (x+3) (x+29 ) = 360
\( x^2+32x -273 = 0\)


(iv) Let the speed of train be x km/h.
Time taken to travel 480 km = \((\frac{480}x +3)\)hrs

In second condition, let the speed of train = (x-8)km/h
It is also given that the train will take 3 hours to cover the same distance. 

Therefore, time taken to travel 480 km = \((\frac{480}x +3)\)hrs 
Speed × Time = Distance 
\((x-8)\) \((\frac{480}x +3)\) = \(480\)
⇒ \(480 + 3x -\frac{3840}{x} -24 \) = \( 480\)
⇒ \(3x - 24x +3840\) = 0
⇒ \(3x^2 -24x +3840\) =0
⇒ \(x^2 -8x +1280\) = 0

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Concepts Used:

Quadratic Equations

A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers

Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.

The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)

Two important points to keep in mind are:

  • A polynomial equation has at least one root.
  • A polynomial equation of degree ‘n’ has ‘n’ roots.

Read More: Nature of Roots of Quadratic Equation

There are basically four methods of solving quadratic equations. They are:

  1. Factoring
  2. Completing the square
  3. Using Quadratic Formula
  4. Taking the square root