The correct answer is option (A): a\(z\)+a\(\bar z\)=0
let \(a=\alpha+i\beta\)
\(z=x+iy\)
Now, \(\bar{a}z+a \bar{z}=0\)
\(\Rightarrow (\alpha-i\beta)(x+iy)+(\alpha+i\beta)(x-iy)=0\)
slope=\(-\frac{\alpha x}{\beta}\)
So, reflection slope = \(\frac{\alpha}{\beta }x\)
Line is \(\alpha x-\beta y=0\rightarrow\)reflection also passes through origin
\(\Rightarrow (\frac{a+\bar{a}}{2})(\frac{z+\bar z}{2})-(\frac{a-\bar a}{2i})(\frac{z-\bar z}{2i})=0\)
\(\Rightarrow az+\bar{az}=0\)
If (-c, c) is the set of all values of x for which the expansion is (7 - 5x)-2/3 is valid, then 5c + 7 =
If A is a square matrix of order 3, then |Adj(Adj A2)| =
Let α,β be the roots of the equation, ax2+bx+c=0.a,b,c are real and sn=αn+βn and \(\begin{vmatrix}3 &1+s_1 &1+s_2\\1+s_1&1+s_2 &1+s_3\\1+s_2&1+s_3 &1+s_4\end{vmatrix}=\frac{k(a+b+c)^2}{a^4}\) then k=
Consider z1 and z2 are two complex numbers.
For example, z1 = 3+4i and z2 = 4+3i
Here a=3, b=4, c=4, d=3
∴z1+ z2 = (a+c)+(b+d)i
⇒z1 + z2 = (3+4)+(4+3)i
⇒z1 + z2 = 7+7i
Properties of addition of complex numbers
It is similar to the addition of complex numbers, such that, z1 - z2 = z1 + ( -z2)
For example: (5+3i) - (2+1i) = (5-2) + (-2-1i) = 3 - 3i
Considering the same value of z1 and z2 , the product of the complex numbers are
z1 * z2 = (ac-bd) + (ad+bc) i
For example: (5+6i) (2+3i) = (5×2) + (6×3)i = 10+18i
Properties of Multiplication of complex numbers
Note: The properties of multiplication of complex numbers are similar to the properties we discussed in addition to complex numbers.
Associative law: Considering three complex numbers, (z1 z2) z3 = z1 (z2 z3)
Read More: Complex Numbers and Quadratic Equations
If z1 / z2 of a complex number is asked, simplify it as z1 (1/z2 )
For example: z1 = 4+2i and z2 = 2 - i
z1 / z2 =(4+2i)×1/(2 - i) = (4+i2)(2/(2²+(-1)² ) + i (-1)/(2²+(-1)² ))
=(4+i2) ((2+i)/5) = 1/5 [8+4i + 2(-1)+1] = 1/5 [8-2+1+41] = 1/5 [7+4i]