Step 1: The formula for the radius of gyration \( K \) of a hollow cylinder about its central axis (the long axis of symmetry) is given by: \[ K = \sqrt{\frac{I}{M}} \] where \( I \) is the moment of inertia and \( M \) is the mass of the hollow cylinder.
Step 2: The moment of inertia \( I \) of a hollow cylinder about its central axis is: \[ I = M R^2 \] where \( R \) is the radius of the hollow cylinder.
Step 3: Substitute the expression for \( I \) into the formula for \( K \): \[ K = \sqrt{\frac{M R^2}{M}} = \sqrt{R^2} = R \] Thus, the radius of gyration \( K \) is equal to the radius \( R \) of the hollow cylinder.
A circular disc has radius \( R_1 \) and thickness \( T_1 \). Another circular disc made of the same material has radius \( R_2 \) and thickness \( T_2 \). If the moments of inertia of both the discs are same and \[ \frac{R_1}{R_2} = 2, \quad \text{then} \quad \frac{T_1}{T_2} = \frac{1}{\alpha}. \] The value of \( \alpha \) is __________.
A solid cylinder of radius $\dfrac{R}{3}$ and length $\dfrac{L}{2}$ is removed along the central axis. Find ratio of initial moment of inertia and moment of inertia of removed cylinder. 