Step 1: The formula for the radius of gyration \( K \) of a hollow cylinder about its central axis (the long axis of symmetry) is given by: \[ K = \sqrt{\frac{I}{M}} \] where \( I \) is the moment of inertia and \( M \) is the mass of the hollow cylinder.
Step 2: The moment of inertia \( I \) of a hollow cylinder about its central axis is: \[ I = M R^2 \] where \( R \) is the radius of the hollow cylinder.
Step 3: Substitute the expression for \( I \) into the formula for \( K \): \[ K = \sqrt{\frac{M R^2}{M}} = \sqrt{R^2} = R \] Thus, the radius of gyration \( K \) is equal to the radius \( R \) of the hollow cylinder.
A, B and C are disc, solid sphere and spherical shell respectively with the same radii and masses. These masses are placed as shown in the figure.
The moment of inertia of the given system about PQ is $ \frac{x}{15} I $, where $ I $ is the moment of inertia of the disc about its diameter. The value of $ x $ is:
A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is :