Radius of a certain orbit of hydrogen atom is 8.48 Å. If energy of electron in this orbit is E/x, then x = ______.
(Given a0 = 0.529Å, E = energy of electron in ground state)
(Given a0 = 0.529Å, E = energy of electron in ground state)
Correct Answer: 16
Solution and Explanation
We know:
\[ r = 0.529 \frac{n^2}{Z} \implies 8.48 = 0.529 \frac{n^2}{1} \]
\[ n^2 = 16 \implies n = 4 \]
We also know:
\[ E \propto \frac{1}{n^2} \]
\[ E_n = \frac{E}{16} \]
Thus, $x = 16$.
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