For a first-order reaction:
\[ t_{1/2} = 120 \, \text{min} \]For 90% completion:
\[ t = \frac{2.303}{k} \log \left( \frac{a}{a - x} \right) \] \[ t = \frac{2.303 \times 120}{0.693} \log \left( \frac{100}{10} \right) \] \[ t = 399 \, \text{min}. \]Initial concentration of [𝐴] 𝑚𝑜𝑙 $𝐿 ^{−1}$ | Initial concentration of [𝐵] 𝑚𝑜𝑙$𝐿 ^{−1}$ | Initial rate of formation of [𝐶] 𝑚𝑜𝑙 $𝐿^{−1} 𝑠 ^{−1}$ |
0.2 | 0.2 | 0.3 |
0.4 | 0.2 | 0.6 |
0.4 | 0.4 | 2.4 |
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