A zero-order reaction is a chemical reaction wherein the rate of reaction does not depend on the concentration of the reactants. The rate remains constant over time.
\[ \text{Rate} = k[\text{Reactant}]^0 = k \] where \(k\) is the rate constant.
To get the overall reaction, add the elementary steps and cancel out species that appear on both sides.
\[ \begin{aligned} \text{Step 1: } & NO(g) + Cl_2(g) \;\;\rightarrow\;\; NOCl_2(g) \\ \text{Step 2: } & NOCl_2(g) + NO(g) \;\;\rightarrow\;\; 2NOCl(g) \\ \hline \text{Overall: } & 2NO(g) + Cl_2(g) \;\;\rightarrow\;\; 2NOCl(g) \end{aligned} \]
A reaction intermediate is a species that is formed in one step of a reaction and consumed in a subsequent step. It does not appear in the overall balanced equation.
In this mechanism, NOCl\(_2\)(g) is formed in Step 1 and consumed in Step 2. Therefore, NOCl\(_2\) is the reaction intermediate.
Rate law for a reaction between $A$ and $B$ is given by $\mathrm{R}=\mathrm{k}[\mathrm{A}]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}}$. If concentration of A is doubled and concentration of B is halved from their initial value, the ratio of new rate of reaction to the initial rate of reaction $\left(\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}}\right)$ is
For $\mathrm{A}_{2}+\mathrm{B}_{2} \rightleftharpoons 2 \mathrm{AB}$ $\mathrm{E}_{\mathrm{a}}$ for forward and backward reaction are 180 and $200 \mathrm{~kJ} \mathrm{~mol}^{-1}$ respectively. If catalyst lowers $\mathrm{E}_{\mathrm{a}}$ for both reaction by $100 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Which of the following statement is correct?