Prove that a cyclic parallelogram is a rectangle.
Solution and Explanation
Let ABCD be a cyclic parallelogram.
∠A = ∠C and ∠B = ∠D
∠A + ∠C = 180° (Opposite angles of a cyclic quadrilateral) ... (1)
We know that opposite angles of a parallelogram are equal.
From equation (1),
∠A + ∠C = 180°
∠A + ∠A = 180°
∠2∠A = 180°
∠A = 90°
Parallelogram ABCD has one of its interior angles as 90°. Therefore, it is a rectangle.
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