From the figure, we have \( \angle BAP = 80^\circ \) and \( \angle ABC = 30^\circ \). Using the property of the angle of a cyclic quadrilateral:
\[
\angle AQC = 180^\circ - \angle BAP - \angle ABC = 180^\circ - 80^\circ - 30^\circ = 55^\circ
\]
Therefore, \( \angle AQC = 55^\circ \).