Question:

A circle touches the sides of a quadrilateral ABCD at points P, Q, R and S then which of the following is true?
A circle touches the sides of a quadrilateral ABCD at points P,Q,R and S then which of the following is true?

Updated On: Apr 17, 2025
  • AB+CD = AD+BC
  • AB+CD > AD+BC
  • AB+CD < AD+BC
  • AB+BC = AD+DC
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

To solve the problem, we need to apply the geometric property of a quadrilateral with an incircle (a circle that touches all four sides of the quadrilateral).

1. Understanding the In-circle Property:
For a quadrilateral that has an incircle (i.e., a circle that touches all four sides), the sum of lengths of opposite sides is equal.
This is a known property of a tangential quadrilateral.

2. Applying the Property:
If a circle touches the sides of quadrilateral $ABCD$ at points $P$, $Q$, $R$, and $S$ as shown in the figure, then:

$ AB + CD = AD + BC $

3. Verifying Options:
Option (1) matches the property: $AB + CD = AD + BC$

Final Answer:
The correct relation is $ \mathbf{AB + CD = AD + BC} $.

Was this answer helpful?
0
0