To solve the problem, we need to apply the geometric property of a quadrilateral with an incircle (a circle that touches all four sides of the quadrilateral).
1. Understanding the In-circle Property:
For a quadrilateral that has an incircle (i.e., a circle that touches all four sides), the sum of lengths of opposite sides is equal.
This is a known property of a tangential quadrilateral.
2. Applying the Property:
If a circle touches the sides of quadrilateral $ABCD$ at points $P$, $Q$, $R$, and $S$ as shown in the figure, then:
$ AB + CD = AD + BC $
3. Verifying Options:
Option (1) matches the property: $AB + CD = AD + BC$
Final Answer:
The correct relation is $ \mathbf{AB + CD = AD + BC} $.
In figure \( \angle BAP = 80^\circ \) and \( \angle ABC = 30^\circ \), then \( \angle AQC \) will be: