Question:
Propyne and propene can be distinguished by
Propyne and propene can be distinguished by
Updated On: July 22, 2025
- concentrated $H_2SO_4$
- $Br_2$ in $CCl_4$
- dilute $KMnO_4$
- $AgNO_3$ in ammonia
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Terminal alkynes forms silver salt with Tollen's reagent while alkene does not react with Tollen's reagent.
$CH_3 - C \equiv C - H+ AgNO_3 \, \, \xrightarrow{NH_3(aq)} CH_3- C \equiv C\, Ag \downarrow $
$\hspace85mm _{}^{white\, ppt}$
Therefore, Tollen's reagent can be used to distinguish a terminal alkyne like propyne from alkene as well as from internal alkynes.
$CH_3 - C \equiv C - H+ AgNO_3 \, \, \xrightarrow{NH_3(aq)} CH_3- C \equiv C\, Ag \downarrow $
$\hspace85mm _{}^{white\, ppt}$
Therefore, Tollen's reagent can be used to distinguish a terminal alkyne like propyne from alkene as well as from internal alkynes.
Was this answer helpful?
0
0
Top Questions on Classification Of Organic Compounds
The correct increasing order of stability of the complexes based on \( \Delta \) value is:
- JEE Main - 2025
- Chemistry
- Classification Of Organic Compounds
Match List-I with List-II: List-I
- JEE Main - 2025
- Chemistry
- Classification Of Organic Compounds
- Which is a heterocyclic compound?
- KEAM - 2025
- Chemistry
- Classification Of Organic Compounds
- Match List I with List II.Choose the correct answer from the options given below:
List I
(Molecule)List II
(Number and types of bond/s between two carbon atoms)A. ethane I. one σ-bond and two π-bonds B. ethene II. two π-bonds C. carbon molecule, C2 III. one σ-bonds D. ethyne IV. one σ-bond and one π-bond - NEET (UG) - 2024
- Chemistry
- Classification Of Organic Compounds
- Among the given organic compounds, the total number of aromatic compounds is
- JEE Main - 2024
- Chemistry
- Classification Of Organic Compounds
View More Questions
Questions Asked in JEE Advanced exam
- Let $$ \alpha = \frac{1}{\sin 60^\circ \sin 61^\circ} + \frac{1}{\sin 62^\circ \sin 63^\circ} + \cdots + \frac{1}{\sin 118^\circ \sin 119^\circ}. $$ Then the value of $$ \left( \frac{\csc 1^\circ}{\alpha} \right)^2 $$ is \rule{1cm}{0.15mm}.
- JEE Advanced - 2025
- Some Applications of Trigonometry
- One of the products formed from the reaction of permanganate ion with iodide ion in neutral aqueous medium is:
- JEE Advanced - 2025
- Redox reactions
- The total number of real solutions of the equation $$ \theta = \tan^{-1}(2 \tan \theta) - \frac{1}{2} \sin^{-1} \left( \frac{6 \tan \theta}{9 + \tan^2 \theta} \right) $$ is
(Here, the inverse trigonometric functions $ \sin^{-1} x $ and $ \tan^{-1} x $ assume values in $[-\frac{\pi}{2}, \frac{\pi}{2}]$ and $(-\frac{\pi}{2}, \frac{\pi}{2})$, respectively.)- JEE Advanced - 2025
- Inverse Trigonometric Functions
Let $ S $ denote the locus of the point of intersection of the pair of lines $$ 4x - 3y = 12\alpha,\quad 4\alpha x + 3\alpha y = 12, $$ where $ \alpha $ varies over the set of non-zero real numbers. Let $ T $ be the tangent to $ S $ passing through the points $ (p, 0) $ and $ (0, q) $, $ q > 0 $, and parallel to the line $ 4x - \frac{3}{\sqrt{2}} y = 0 $.
Then the value of $ pq $ is- JEE Advanced - 2025
- Coordinate Geometry
- Let $ \mathbb{R} $ denote the set of all real numbers. Let $ a_i, b_i \in \mathbb{R} $ for $ i \in \{1, 2, 3\} $.
Define the functions $ f: \mathbb{R} \to \mathbb{R},\ g: \mathbb{R} \to \mathbb{R},\ h: \mathbb{R} \to \mathbb{R} $ by:
$$ f(x) = a_1 + 10x + a_2x^2 + a_3x^3 + x^4,\quad g(x) = b_1 + 3x + b_2x^2 + b_3x^3 + x^4, $$ $$ h(x) = f(x+1) - g(x+2) $$ If $ f(x) \ne g(x) $ for every $ x \in \mathbb{R} $, then the coefficient of $ x^3 $ in $ h(x) $ is:- JEE Advanced - 2025
- Polynomials
View More Questions
JEE Advanced Notification
GMC Azamgarh Admission 2025: Dates, Courses, Fees, Eligibility, SelectJuly 22, 2025GMC Azamgarh Admission 2025
Concepts Used:
Classification of Organic Compounds
Organic Compounds can be classified into:
Classification based on the structure:
The classification of organic compounds is based on structure such as:
- Acyclic or open chain compounds - Acyclic compounds are just opposite to cyclic compounds because their molecules don’t form any ring. It is called open-chain compounds because they have a linear structure.
- Cyclic or closed chain compounds - Cyclic compounds are also known as “Ring compounds.”