Question:
PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
Updated On: Dec 8, 2023
Hide Solution
Verified By Collegedunia
Solution and Explanation
By applying Pythagoras theorem in \(Δ\;PQR\),
\(\Rightarrow\) \((PQ)^2+ (PR)^2= (RQ)^2\)
\(\Rightarrow\) \((10)^2+ (24)^2= RQ^2\)
\(\Rightarrow\) \(100 + 576 = (QR)^2\)
\(\Rightarrow\) \(676 = (QR)^2\)
\(\Rightarrow\)\(QR= 26\) \(cm\)
Was this answer helpful?
0
0
Top Questions on Right-Angled Triangles And Pythagoras Property
- The altitude of a right-angled triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.
- UP Board X - 2025
- Mathematics
- Right-Angled Triangles And Pythagoras Property
एक कातळकोन त्रिकोणामध्ये कातळकोन करणाया बाजू 9 सेमी व 12 सेमी आहे, तर त्या त्रिकोणाच्या कर्णाची लांबी काय असेल?
- Maharashtra Class X Board - 2024
- Mathematics Geometry
- Right-Angled Triangles And Pythagoras Property
- A ladder 25 feet long is leaning against a wall such that it touches 24 feet high window. How far is the foot of the ladder from the wall?
- CUET (UG) - 2023
- Mathematics
- Right-Angled Triangles And Pythagoras Property
- In the below figure \(△PQR~△ABC\), then \(z+y=\) _____ .
- TS POLYCET - 2022
- Mathematics
- Right-Angled Triangles And Pythagoras Property
- The angle of elevation of the top of a tower, whose height is 100 m, at a point whose distance from the base of the tower is 100 m is
- TS POLYCET - 2021
- Mathematics
- Right-Angled Triangles And Pythagoras Property
View More Questions
Questions Asked in CBSE Class VII exam
- Express each of the following as a product of prime factors only in exponential form:
(i) 108 × 192 (ii) 270 (iii) 729 × 64 (iv) 768- CBSE Class VII
- Exponents and Powers
- From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (Take \(\pi\) = \(\frac{22}{ 7}\) )
- CBSE Class VII
- Circles
- The points P, Q, R, S, T, U, A and B on the number line are such that, TR = RS = SU and AP = PQ = QB. Name the rational numbers represented by P, Q, R and S.
- CBSE Class VII
- Need For Rational Numbers
- Multiply and reduce to lowest form (if possible) :
(i) \(\frac{2}{3}\) × 2 \(\frac{2}{3}\)
(ii) \(\frac{2}{7}\) × \(\frac{7}{9}\)
(iii) \(\frac{3}{8}\) × \(\frac{6}{4}\)
(iv) \(\frac{9}{4}\) × \(\frac{3}{5}\)
(v) \(\frac{1}{3}\)× \(\frac{15}{8}\)
(vi) \(\frac{11}{2}\) × \(\frac{3}{10}\)
(vii) \(\frac{4}{5}\) × \(\frac{12}{7}\)- CBSE Class VII
- Multiplication Of Fractions
- Find the product:
(i)\(\frac{9}{2}\)×(-\(\frac{7}{4}\))
(ii) \(\frac{3}{10}\)×(-9)
(iii) -\(\frac{6}{5}\)×\(\frac{9}{11}\)
(iv) \(\frac{3}{7}\)×(-\(\frac{2}{5}\))
(v) \(\frac{3}{11}\)×\(\frac{2}{5}\)
(vi) \(\frac{3}{-5}\) ×\(\frac{-5}{3}\)- CBSE Class VII
- Operations On Rational Numbers
View More Questions