Question:
Potential difference between $A$ and $B$ in the following circuit
Potential difference between $A$ and $B$ in the following circuit
Updated On: Apr 18, 2024
- 4 V
- 5.6 V
- 2.8 V
- 6 V
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The Correct Option is B
Solution and Explanation
Apply Kirchhoff's second loop law, go from $A$ to $B$ anti-clockwise
$I(2+8) =6-4 $
$I \cdot 10 =2 $
$I =0.2 A$
$V_{A}-I \times 2+6 =V_{B} $
$V_{A}-V_{B} =0 \cdot 2 \times 2-6 $
$=0.4-6=-5.6 \,V$
Hence, $V_{A} < V_{B}$
and $V_{B A}=5.6 \,V$
$I(2+8) =6-4 $
$I \cdot 10 =2 $
$I =0.2 A$
$V_{A}-I \times 2+6 =V_{B} $
$V_{A}-V_{B} =0 \cdot 2 \times 2-6 $
$=0.4-6=-5.6 \,V$
Hence, $V_{A} < V_{B}$
and $V_{B A}=5.6 \,V$
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Concepts Used:
Kirchhoff's Laws
Kirchhoffs Circuit Laws allow us to solve complex circuit problems.
Kirchhoff's First Law/ Kirchhoffs Current Law
It states that the “total current or charge entering a junction or node is exactly equal to the charge leaving the node as it has no other place to go except to leave, as no charge is lost within the node“.
Kirchhoff's Second Law/ Kirchhoffs Voltage Law
It states that “in any closed loop network, the total voltage around the loop is equal to the sum of all the voltage drops within the same loop” which is also equal to zero.