Question:
$∫_{-\pi}^{\pi} \frac{2x(1+sinx)}{1+cos^2x}dx $ is equal to?
$∫_{-\pi}^{\pi} \frac{2x(1+sinx)}{1+cos^2x}dx $ is equal to?
Updated On: Apr 6, 2024
- $π^2$
- $2π$
- $\frac{3π}2$
- $\frac{π^2}2$
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The Correct Option is A
Solution and Explanation
The Correct answer is option is (A) : $π^2$
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