The reaction of phenol with chloroform in the presence of sodium hydroxide, followed by hydrolysis in an acidic medium, is known as the Reimer-Tiemann reaction. This reaction results in the formation of 2-hydroxybenzaldehyde (commonly known as salicylaldehyde). The reaction can be represented as:
\(\text{Phenol} + \text{CHCl}_3 + \text{NaOH} \rightarrow 2\text{-Hydroxybenzaldehyde (salicylaldehyde)}\)
The reaction involves the introduction of a formyl group (-CHO) at the ortho position relative to the hydroxyl group (-OH), producing 2-hydroxybenzaldehyde.
The Correct Answer is: 2-Hydroxybenzaldehyde
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32