1. $\mathrm{V}^{2+}$:
- $\mathrm{V}^{2+} \Rightarrow 3 \mathrm{~d}^{3} 4 \mathrm{~s}^{0}$
- Number of unpaired electrons = 3
2. $\mathrm{Co}^{2+}$:
- $\mathrm{Co}^{2+} \Rightarrow 3 \mathrm{~d}^{7} 4 \mathrm{~s}^{0}$
- Number of unpaired electrons = 3
3. $\mathrm{Ti}^{2+}$:
- $\mathrm{Ti}^{2+} \Rightarrow 3 \mathrm{~d}^{2} 4 \mathrm{~s}^{0}$
- Number of unpaired electrons = 2
4. $\mathrm{Fe}^{3+}$:
- $\mathrm{Fe}^{3+} \Rightarrow 3 \mathrm{~d}^{5} 4 \mathrm{~s}^{0}$
- Number of unpaired electrons = 5
5. $\mathrm{Cr}^{2+}$:
- $\mathrm{Cr}^{2+} \Rightarrow 3 \mathrm{~d}^{4} 4 \mathrm{~s}^{0}$
- Number of unpaired electrons = 4
6. $\mathrm{Ti}^{3+}$:
- $\mathrm{Ti}^{3+} \Rightarrow 3 \mathrm{~d}^{1} 4 \mathrm{~s}^{0}$
- Number of unpaired electrons = 1
7. $\mathrm{Mn}^{2+}$:
- $\mathrm{Mn}^{2+} \Rightarrow 3 \mathrm{~d}^{5} 4 \mathrm{~s}^{0}$
- Number of unpaired electrons = 5
Therefore, the correct answer is (1) $\mathrm{V}^{2+}, \mathrm{Co}^{2+}$.