Question

This oxide is most basic. [Ti=22, V=23, Cr=24, Fe=26]

• A. FeO
• B. VO
• C. CrO
• D. TiO

Hint:

Basicity of metal oxides increases as the oxidation state decreases, and Titanium(II) oxide is a strong base.

Answer 1

The Correct Option is D

Step 1: Identify the metal oxides and their properties
The given metals are Titanium (Ti), Vanadium (V), Chromium (Cr), and Iron (Fe), each forming an oxide with varying basicity. Oxides of metals tend to be basic or acidic depending on the metal's position in the periodic table.
Step 2: Analyze the given options

• FeO (Iron(II) oxide): Iron(II) oxide is relatively basic but less so compared to Titanium oxides.
• VO (Vanadium monoxide): Vanadium oxides are typically less basic and more acidic.
• CrO (Chromium(II) oxide): Chromium oxides also have moderate basicity but are not the most basic of the options.
• TiO (Titanium(II) oxide): Titanium oxides are highly basic due to the low electronegativity and high metallic character of Titanium.

Step 3: Conclusion
Titanium oxide (TiO) is the most basic oxide among the options given, as Titanium is in a lower oxidation state and its oxide shows strong basic behavior.
Conclusion:

TiO is the most basic oxide.