Let \( \alpha \) and \( \beta \) be real numbers such that \( f(x) \) is defined as:
\[
f(x) =
\begin{cases}
2x^2 + 4x + \alpha, & \text{if } x < 1 \\
\beta x^2 + 5, & \text{if } x \geq 1
\end{cases}
\]
and is differentiable at \( x = 1 \). Then \( \alpha + \beta \) is equal to: