Question:
Out of [Co(NH\(_3\))\(_6\)]\(^{3+}\) and [Co(NH\(_3\))\(_4\)Cl\(_2\)]\(^+\), which complex is heteroleptic and why?
Out of [Co(NH\(_3\))\(_6\)]\(^{3+}\) and [Co(NH\(_3\))\(_4\)Cl\(_2\)]\(^+\), which complex is heteroleptic and why?
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- Heteroleptic complexes contain more than one type of ligand.
- Homoleptic complexes contain only one type of ligand.
Updated On: Feb 25, 2025
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Solution and Explanation
The complex [Co(NH\(_3\))\(_4\)Cl\(_2\)]\(^+\) is heteroleptic because it contains two different types of ligands (NH\(_3\) and Cl\(^-\)). In contrast, [Co(NH\(_3\))\(_6\)]\(^{3+}\) is homoleptic as it contains only one type of ligand (NH\(_3\)).
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