Question

One mole of helium gas, initially at STP (p₁ = 1 atm, T₁ = 0°C), undergoes an isovolumetric process in which its pressure falls to half its initial value. The work done by the gas is:

• A. 101 J
• B. 51 J
• C. 23 J
• D. 0 J

Hint:

In an isovolumetric process, the volume remains constant, meaning no work is done by the gas.

Answer 1

The Correct Option is D

In an isovolumetric process, the volume remains constant, and since work is given by \( W = P \Delta V \), the work done by the gas is zero because the volume does not change: \[ W = 0 \] Thus, the work done by the gas is 0 J.