
The work done in a cyclic process is equal to the area enclosed by the process on the PV diagram. The work done by the gas in the given cycle can be calculated by evaluating this enclosed area, which gives \( 10 P_0 V_0 \).
The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: 