One mole of an ideal monatomic gas is taken round the cyclic process \( MNOM \). The work done by the gas is
- 4.5 \( P_0 V_0 \)
- \( 9 P_0 V_0 \)
- \( 10 P_0 V_0 \)
- \( 2 P_0 V_0 \)
The Correct Option is C
Solution and Explanation
The work done in a cyclic process is equal to the area enclosed by the process on the PV diagram. The work done by the gas in the given cycle can be calculated by evaluating this enclosed area, which gives \( 10 P_0 V_0 \).
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