The distance of the point \( P(-3,4,5) \) from the yz-plane is:
Show Hint
- 5 units
- 3 units
- 4 units
- 3 units
The Correct Option is C
Solution and Explanation
The distance of any point from the yz-plane is simply the absolute value of its x-coordinate. For the point \( P(-3, 4, 5) \), the distance from the yz-plane is: \[ |x| = |-3| = 3 \, \text{units} \] Thus, the distance from the yz-plane is 3 units.
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