\[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \] $2 \, \text{Faraday} \rightarrow 1 \, \text{mol Cu}$ $1 \, \text{Faraday} \rightarrow 0.5 \, \text{mol Cu deposit}$$0.5 \, \text{mol} = 0.5 \, \text{g atom} = 5 \times 10^{-1}$ \[ x = 5 \]