Relationship Between Celsius and Fahrenheit Scales:
The relationship between temperature changes on the Celsius scale (\( \Delta C \)) and the Fahrenheit scale (\( \Delta F \)) is given by:
\[ \Delta F = \Delta C \times 1.8 \]
Calculate the Change in Fahrenheit:
Given \( \Delta C = 40^\circ C \),
we can find \( \Delta F \) as follows:
\[ \Delta F = 40 \times 1.8 = 72^\circ F \]
Conclusion:
The increase in temperature on the Fahrenheit scale corresponding to a \( 40^\circ C \) increase is \( 72^\circ F \).
Let \( S = \left\{ m \in \mathbb{Z} : A^m + A^m = 3I - A^{-6} \right\} \), where
\[ A = \begin{bmatrix} 2 & -1 \\ 1 & 0 \end{bmatrix} \]Then \( n(S) \) is equal to ______.
The number of 6-letter words, with or without meaning, that can be formed using the letters of the word MATHS such that any letter that appears in the word must appear at least twice, is $ 4 \_\_\_\_\_$.
Let \( f : (0, \infty) \to \mathbb{R} \) be a twice differentiable function. If for some \( a \neq 0 \), } \[ \int_0^a f(x) \, dx = f(a), \quad f(1) = 1, \quad f(16) = \frac{1}{8}, \quad \text{then } 16 - f^{-1}\left( \frac{1}{16} \right) \text{ is equal to:}\]
Let $L_1: \frac{x-1}{1} = \frac{y-2}{-1} = \frac{z-1}{2}$ and $L_2: \frac{x+1}{-1} = \frac{y-2}{2} = \frac{z}{1}$ be two lines. Let $L_3$ be a line passing through the point $(\alpha, \beta, \gamma)$ and be perpendicular to both $L_1$ and $L_2$. If $L_3$ intersects $L_1$, then $\left| 5\alpha - 11\beta - 8\gamma \right|$ equals: